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NCERT Exemplar Class 7 Maths Chapter 9 MCQ

NCERT Exemplar Class 7 Maths Chapter 9 MCQ : Prepare for your exams with our comprehensive Maths MCQ quiz. These questions cover key concepts including Fractions and Decimals, Perimeter and Area, Integers, Algebraic Expressions, and Data Handling, directly aligned with the NCERT Exemplar guidelines. Use this practice test to verify your understanding of Maths and related concepts.

NCERT Exemplar Class 7 Maths Chapter 9 MCQ

Study Class 7 Maths Chapter 9 MCQ quiz with Free NCERT Quiz, Free Exemplar MCQ with answers and Ncert Exemplar MCQ. Complete this free online MCQ quiz aligned with NCERT guidelines.

30 Multiple Choice Questions
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Total Marks: 30

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1 out of 30 questions

The numerator of a rational number 8 is
The denominator of the rational number 8 is
The numerator of the rational number – 9 is
The denominator of the rational number – 9 is
If \(\frac { 3 }{ 4 } \) = \(\frac { ? }{ 12 } \), then ? =
if \(\frac { 4 }{ 5 } \) = \(\frac { 12 }{ ? } \), then ? =
if \(\frac { -4 }{ 7 } \) = \(\frac { ? }{ 14 } \), then ? =
if \(\frac { -7 }{ 11 } \) = \(\frac { 14 }{ ? } \), then ? =
if \(\frac { -3 }{ -5 } \) = \(\frac { 9 }{ ? } \), then ? =
if \(\frac { -8 }{ -9 } \) = \(\frac { -16 }{ ? } \), then ? =
Which of the following is a negative rational number?
Which of the following is a positive rational number?
The rational number \(\frac { 12 }{ 40 } \) in standard 40 form is
The rational number \(\frac { -21 }{ 28 } \) in standard form is
The rational number \(\frac { -6 }{ -25 } \) in standard form is
Which of the following rational numbers -2 is equivalent to \(\frac { -2 }{ 5 } \) ?
Which of the following rational numbers is not equivalent to \(\frac { 7 }{ -4 } \) ?
Which of the following rational numbers is not to equivalent to \(\frac { 3 }{ 5 } \) ?
Which of the following is correct?
Which of the following is correct?
Which of the following is correct?
The reciprocal of \(\frac { -2 }{ 5 } \) is
The sum \(\frac { 5 }{ 4 } \) + (- \(\frac { 25 }{ 4 } \)) =
The sum –\(\frac { 3 }{ 4 } \) + 0 =
\(\frac { 17 }{ 11 } \) – \(\frac { 6 }{ 11 } \) =
\(\frac { 2 }{ -5 } \) × \(\frac { -5 }{ 2 } \) =
–\(\frac { 6 }{ 5 } \) × 1 =
–\(\frac { 6 }{ 5 } \) + 1 =
\(\frac { 2 }{ 9 } \) × \(\frac { 27 }{ 8 } \) =
\(\frac { 7 }{ 12 } \) ÷ ( –\(\frac { 7 }{ 12 } \)) =

NCERT Exemplar PDF Free Download (class 6 to 10)

Class Subject Total Questions Total Units Link
Class VI Mathematics 319 25 View →
Class VII Mathematics 600 19 View →
Class VIII Mathematics 740 31 View →
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Class X Mathematics 1,944 34 View →
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Class XII Mathematics 788 56 View →